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RileyT
@RileyT
April 2019
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Bonjour ! J'aurais besoin d'aide pour cet exercice de maths...merci beaucoup !
( * veut dire au carré)
D= (2a+1)* + (2a+1)(a-3)
1- développer et réduire D
2- factoriser D
3- calculer D pour a= -2
Merci !
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yayane97
D= 2a
²-4a+1+2a
²+6a+a-3
D = 4a
²+3a-2
Factorisation : a(4a+3)-2
si a=2 alors D= 2(4x2+3)-2
D = 2(8+3)-2
D= 16+6-2=20
0 votes
Thanks 1
lyne99
1) 4a²+1+4a+2a²-6a+a-3
= 6a²-a-2
2) (2a+1)(2a+1+a-3)
=(2a+1)(3a-2)
3) 6x(-2)²-(-2)-2
= 6x4+2+2
= 24+4
= 28
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Thanks 1
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Bonjour, j'ai vraiment besoin de votre aide pour cet exercice : Consigne : Factoriser en mettant (y+1) en facteur. A= 3y + 3 B= (y+1)(y+5) + 7(y+1) C= (y+1)(8y-3) - (y-7)(y+1) D= (y+1)(8y-3) + 4y + 4 Merci beaucoup d'avance !
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D = 4a²+3a-2
Factorisation : a(4a+3)-2
si a=2 alors D= 2(4x2+3)-2
D = 2(8+3)-2
D= 16+6-2=20
= 6a²-a-2
2) (2a+1)(2a+1+a-3)
=(2a+1)(3a-2)
3) 6x(-2)²-(-2)-2
= 6x4+2+2
= 24+4
= 28