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Haraimi
@Haraimi
April 2019
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Bonjour, j'aurais besoin d'aide pour un exercice de math que je n'ai pas compris parce que j'étais absente. Merci à ceux qui essaieront de m'aider.
Je dois calculer trois systèmes (systèmes à deux inconnus) :
1) { x- 2y = 0
2x + y= -5
2) { x- 2y = 0
x-y = 2
3) { x- y = 2
2x +y = -5
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choupp
1)
x
- 2y = 0
2
x
+ y= -5
x =
0 + 2y
(on isole x)
2
( 0 + 2y)
+ y = -5
(et on remplace)
x = 0 + 2y
5y = -5
y = -1
x = -2
2)
x- 2y = 0
x-y = 2
x = 0 + 2y
0 + 2y - y = 2
y = 2
x = 4
3)
x- y = 2
2x +y = -5
x = 2 + y
2 (2+y) +y = -5
x = 2 + y
4 + 3y = -5
x = 2 + y
3y = -9
y = -3
x = -1
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2x + y= -5
x = 0 + 2y (on isole x)
2 ( 0 + 2y) + y = -5 (et on remplace)
x = 0 + 2y
5y = -5
y = -1
x = -2
2) x- 2y = 0
x-y = 2
x = 0 + 2y
0 + 2y - y = 2
y = 2
x = 4
3) x- y = 2
2x +y = -5
x = 2 + y
2 (2+y) +y = -5
x = 2 + y
4 + 3y = -5
x = 2 + y
3y = -9
y = -3
x = -1