a=-1 , b=3 , c=0
Δ = b² - 4ac ⇒ Δ = 3²- 4*(-1)*0 =9
Δ> 0, l’équation admet 2 solutions x1 = (-b -√Δ) /2a ⇒ x1 = (-3- √9) / -2
x1 = -6/2 = -3
x2 = (-b+√Δ)/2a ⇒x2 =(-3+√9)/-2 = (-3+3)/2 = 0
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a=-1 , b=3 , c=0
Δ = b² - 4ac ⇒ Δ = 3²- 4*(-1)*0 =9
Δ> 0, l’équation admet 2 solutions x1 = (-b -√Δ) /2a ⇒ x1 = (-3- √9) / -2
x1 = -6/2 = -3
x2 = (-b+√Δ)/2a ⇒x2 =(-3+√9)/-2 = (-3+3)/2 = 0