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david311
@david311
January 2021
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Bonjour je dois résoudre cette équation mais je suis complètement bloqué pouvez vous m’aidez svp
Merci d’avance !!
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ProfdeMaths1
Verified answer
Sin(2x+π/4)=sin(x)
2x+π/4=x+2kπ ou 2x+π/4=π-x+2kπ
x=-π/4+2kπ ou 3x=3π/4+2kπ
x=
-π/4+2kπ
ou x=
π/4+2kπ/3
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Verified answer
Sin(2x+π/4)=sin(x)2x+π/4=x+2kπ ou 2x+π/4=π-x+2kπ
x=-π/4+2kπ ou 3x=3π/4+2kπ
x=-π/4+2kπ ou x=π/4+2kπ/3