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OTB27
@OTB27
May 2019
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Bonjour je n arrive pas à résoudre par le calcul f(x)=-x³+4x f(x)=0 et g(x)=-x²+4 g(x)=0
merci
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greencalogero
Verified answer
Bonjour,
f(x)=0
-x³+4x=0
4-x²=0
(x+2)(x-2)=0
x=2 ou x=-2 donc S=[-2;2]
g(x)=0
4-x²=0
g(x)=f(x)=0
donc S=[-2;2]
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greencalogero
c'est vraie, il manque x=0
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Lista de comentários
Verified answer
Bonjour,f(x)=0
-x³+4x=0
4-x²=0
(x+2)(x-2)=0
x=2 ou x=-2 donc S=[-2;2]
g(x)=0
4-x²=0
g(x)=f(x)=0
donc S=[-2;2]