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MinatoNM
@MinatoNM
January 2021
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Bonjour je n'arrive pas en particulier le 1), c'est sur les ondes mécanique.
Merci pour votre aides.
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scoladan
Verified answer
Bonjour,
1) Les intensités s'ajoutent :
I(source 1) = I₀ x 10^(L/10) et I(source 2) = I₀ x 10^(L/10)
avec I en W.m⁻² , L en dB et I₀ = 1,0.10⁻¹² W.m⁻²
L = 70 dB pour les 2 sources, donc :
I(totale) = 2 x 1,0.10⁻¹² x 10⁷ = 2,0.10⁻⁵ W.m⁻²
2) Niveau sonore total : L = 10log(I/I₀)
⇒ L(total) = 10log(2,0.10⁻⁵/1,0.10⁻¹²) = 73 dB
3) Augmentation de niveau sonore : 73 - 70 = 3 dB
2 votes
Thanks 0
MinatoNM
Merci je comprend mieux maintenons :)
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Verified answer
Bonjour,1) Les intensités s'ajoutent :
I(source 1) = I₀ x 10^(L/10) et I(source 2) = I₀ x 10^(L/10)
avec I en W.m⁻² , L en dB et I₀ = 1,0.10⁻¹² W.m⁻²
L = 70 dB pour les 2 sources, donc :
I(totale) = 2 x 1,0.10⁻¹² x 10⁷ = 2,0.10⁻⁵ W.m⁻²
2) Niveau sonore total : L = 10log(I/I₀)
⇒ L(total) = 10log(2,0.10⁻⁵/1,0.10⁻¹²) = 73 dB
3) Augmentation de niveau sonore : 73 - 70 = 3 dB