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Gang193
@Gang193
May 2019
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Bonjour ,
Je poste ce devoir car j'ai commencé à le faire mais je n'y arrive pas totalement s'il serait possible de m'aider s'il vous plait c'est assez urgent . Je vous en remercie d'avance
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scoladan
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Bonjour,
1) Différence de pression DeltaP = p(eau) x g x h
= 1000 x 9,81 x 26,2 = 257022 Pa
Débit Q = 45 m^3/h = 45/3600 m^3.s^-1
==> Phydro = Q x DeltaP
= 45/3600 x 257022 = 3213 W
2) Phydro/Pméca = 68% = 0,68
==> Pméca = Phydro/0,68 = 4725 W
3) w = 3000 trs//mn = 3000/3600 trs/s = 3000x2pi/3600 rad.s^-1 = 5pi/3 rad.s^-1
Couple T = Pméca/w
==> T = 4725/(5pi/3) = 902 N.m
4) Pméca/Pélec = 85% = 0,85
==> Pélec = Pméca/0,85 = 4725/0,85 = 5559 W
5) Rendement global = Phydro/Pélec = 3213/5559 = 0,58 = 58%
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Verified answer
Bonjour,1) Différence de pression DeltaP = p(eau) x g x h
= 1000 x 9,81 x 26,2 = 257022 Pa
Débit Q = 45 m^3/h = 45/3600 m^3.s^-1
==> Phydro = Q x DeltaP
= 45/3600 x 257022 = 3213 W
2) Phydro/Pméca = 68% = 0,68
==> Pméca = Phydro/0,68 = 4725 W
3) w = 3000 trs//mn = 3000/3600 trs/s = 3000x2pi/3600 rad.s^-1 = 5pi/3 rad.s^-1
Couple T = Pméca/w
==> T = 4725/(5pi/3) = 902 N.m
4) Pméca/Pélec = 85% = 0,85
==> Pélec = Pméca/0,85 = 4725/0,85 = 5559 W
5) Rendement global = Phydro/Pélec = 3213/5559 = 0,58 = 58%