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Puchiko
@Puchiko
May 2019
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Bonjour,
Je rencontre un petit problème avec les factorisations. Un peu d'aide pour démarrer ne serait pas de refus.
4( 2x - 2 )( 2x - 4 ) -2( 2x - 2 )^{2}
Merci d'avance pour votre aide
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ProfdeMaths1
Verified answer
4( 2x - 2 )( 2x - 4 ) -2( 2x - 2 )²
=(2x-2)(4(2x-4)-2(2x-2))
=(2x-2)(8x-16-4x+4)
=(2x-2)(4x-12)
=8(x-1)(x-3)
2 votes
Thanks 0
taalbabachir
4(2 x - 2)(2 x - 4) - 2(2 X - 2)²
(2 x - 2)[4(2 x - 4) - 2(2 x - 2)]
(2 x - 2)(8 x - 16 - 4 x + 4)
(2 x - 2)(4 x - 12)
8(x - 1)(x - 3)
0 votes
Thanks 0
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Verified answer
4( 2x - 2 )( 2x - 4 ) -2( 2x - 2 )²=(2x-2)(4(2x-4)-2(2x-2))
=(2x-2)(8x-16-4x+4)
=(2x-2)(4x-12)
=8(x-1)(x-3)
(2 x - 2)[4(2 x - 4) - 2(2 x - 2)]
(2 x - 2)(8 x - 16 - 4 x + 4)
(2 x - 2)(4 x - 12)
8(x - 1)(x - 3)