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Controle4c
@Controle4c
May 2019
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Bonjour je suis en 3ème et ce serez pour savoir si vous pouvez m'aider merci
C= (4x-3)(x-1) - 5(4x-3)
1. Développez et réduis C
2. Factorisez C
Merci beaucoup de votre aide
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swnn
Verified answer
1. C = (4x-3)(x-1)-5(4x-3)
C = 4x²-4x-3x+3-20x+15
C = 4x²-27x+18
2. facteur commun (4x-3)
C = (4x-3)[(x-1)-5]
C = (4x-3)(x-1-5)
C = (4x-3)(x-6)
0 votes
Thanks 1
Controle4c
merci beaucoup
Sulky
Verified answer
Bonjour,
Développement et réduction :
C= (4x-3)(x-1) - 5(4x-3)
C = 4x
² - 4x - 3x + 3 - 20x + 15
C = 4x² - 27x + 18
Factorisation :
C= (4x-3)(x-1) - 5(4x-3)
C = (4x - 3)(x - 1 - 5)
C = (4x - 3)(x - 6)
1 votes
Thanks 1
Controle4c
Merci encore
Sulky
je t'en prie :)
Controle4c
;p
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Verified answer
1. C = (4x-3)(x-1)-5(4x-3)C = 4x²-4x-3x+3-20x+15
C = 4x²-27x+18
2. facteur commun (4x-3)
C = (4x-3)[(x-1)-5]
C = (4x-3)(x-1-5)
C = (4x-3)(x-6)
Verified answer
Bonjour,Développement et réduction :
C= (4x-3)(x-1) - 5(4x-3)
C = 4x² - 4x - 3x + 3 - 20x + 15
C = 4x² - 27x + 18
Factorisation :
C= (4x-3)(x-1) - 5(4x-3)
C = (4x - 3)(x - 1 - 5)
C = (4x - 3)(x - 6)