Bonjour,
1) r(x) = 2(x+7) donc r(4) = 2(4+7) = 22
2) d(x) = πx² donc d(1,5) = π1,5² = 2,25π ≅ 7,1
3) l(x) = 4x donc si l(x) = 24 alors 4x = 24 donc x = 24/4 = 6
4) t(x) = 2(x+2)/2 = x+2 donc t(3) = 3+2 = 5
5) c(x) = x² donc si c(x) = 49 alors x² = 49 donc x = 7
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Bonjour,
1) r(x) = 2(x+7) donc r(4) = 2(4+7) = 22
2) d(x) = πx² donc d(1,5) = π1,5² = 2,25π ≅ 7,1
3) l(x) = 4x donc si l(x) = 24 alors 4x = 24 donc x = 24/4 = 6
4) t(x) = 2(x+2)/2 = x+2 donc t(3) = 3+2 = 5
5) c(x) = x² donc si c(x) = 49 alors x² = 49 donc x = 7