Réponse :
Ex 1
1- A = √50*2 = √100 = 10.
B = √72/18 = √4 = 2.
2- La condition: b doit être le plus petit possible dans a√b:
C= √32 = √2*16 = √2*√16 = 4√2.
D = √75 = √25*3 = √25*√3 = 5√3.
3- E = (14-6+3)√7 = 11√7. il suffit de factoriser.
F = (2√9*5) - (7√16*5) = 2(√9*√5) - 7(√16*√5) = 2*3*√5 - 7*4*√5
= 6√5 - 28√5 = (6-28)√5 = -22√5.
4- G = 3-π.
Med
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Réponse :
Ex 1
1- A = √50*2 = √100 = 10.
B = √72/18 = √4 = 2.
2- La condition: b doit être le plus petit possible dans a√b:
C= √32 = √2*16 = √2*√16 = 4√2.
D = √75 = √25*3 = √25*√3 = 5√3.
3- E = (14-6+3)√7 = 11√7. il suffit de factoriser.
F = (2√9*5) - (7√16*5) = 2(√9*√5) - 7(√16*√5) = 2*3*√5 - 7*4*√5
= 6√5 - 28√5 = (6-28)√5 = -22√5.
4- G = 3-π.
Med