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Juju18MAI
@Juju18MAI
April 2019
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Bonjour, je suis un peu perdue, pourriez vous m'aider?
On considère l'expression E=(3x+2)² -(5x-3) (3x+2)
1)Dévelloper et reduire E
2)Factoriser E
3)Calculer E pour x=-2
4) Ressoudre l'équation (3x+2) (5x-3)=0
Merci D'avance
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lamarocainemrk
1) E= (3x+2)² - (5x-3)(3x+2)
=(3x)²+2*3x*2 +2² - 15x² -10x -9x-6
= 9x²+12x+4-15x²-19x-6
= -6x² -7x-2 = - (6x²+7x+2)
2) E=(3x+2)² -(5x-3)(3x+2)
=(3x+2)(3x+2)-(5x-3)(3x+2)
=(3x+2)(3x+2-5x+3)
=(3x+2)(-2x+5)
3)
on a E=(3x+2)(-2x+5) , soit x=-2
E=(3*(-2)+2)(-2*(-2)+5)
E=
(-6+2)(4+5)
E=-4*9
E=-36
4) Résolvons l'équation (3x+2)(5x-3) = 0
3x+2=0 ou 5x-3=0
3x=-2 ou 5x=3
x=-2/3 ou x=3/5
cette équation admet deux solutions
-2/3 et 3/5
,
S=(-2/3 ; 3/5)
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=(3x)²+2*3x*2 +2² - 15x² -10x -9x-6
= 9x²+12x+4-15x²-19x-6
= -6x² -7x-2 = - (6x²+7x+2)
2) E=(3x+2)² -(5x-3)(3x+2)
=(3x+2)(3x+2)-(5x-3)(3x+2)
=(3x+2)(3x+2-5x+3)
=(3x+2)(-2x+5)
3) on a E=(3x+2)(-2x+5) , soit x=-2
E=(3*(-2)+2)(-2*(-2)+5)
E=(-6+2)(4+5)
E=-4*9
E=-36
4) Résolvons l'équation (3x+2)(5x-3) = 0
3x+2=0 ou 5x-3=0
3x=-2 ou 5x=3
x=-2/3 ou x=3/5
cette équation admet deux solutions -2/3 et 3/5 , S=(-2/3 ; 3/5)