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MrDro
@MrDro
May 2019
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Bonjour,
Mettre sous forme canonique le polynôme P(x)=x²+10x+5 :
Merci de m'aider
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ProfdeMaths1
Verified answer
P(x)=x²+10x+5
=x²+10x+25-20
=
(x+5)²-20
1 votes
Thanks 1
MonsieurFirdown
Verified answer
Bonjour
♧ On a P(x) = x² + 10x + 5 d'où a = 1 , b = 10 et c = 5 ..
♧ On a donc :
● Alpha =
● Bêta = P(Alpha) d'où Bêta égale à :
P(-5) = (-5)²+10×(-5) + 5 = 25 - 50 + 5 = - 20
♧ Conclusion : la forme canonique de P(x) est : (x+5)² - 20
Voilà ^^
2 votes
Thanks 1
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Verified answer
P(x)=x²+10x+5=x²+10x+25-20
=(x+5)²-20
Verified answer
Bonjour♧ On a P(x) = x² + 10x + 5 d'où a = 1 , b = 10 et c = 5 ..
♧ On a donc :
● Alpha =
● Bêta = P(Alpha) d'où Bêta égale à :
P(-5) = (-5)²+10×(-5) + 5 = 25 - 50 + 5 = - 20
♧ Conclusion : la forme canonique de P(x) est : (x+5)² - 20
Voilà ^^