Articles
Register
Sign In
Search
Liorasarah
@Liorasarah
May 2019
2
89
Report
Bonjour, notre prof nous a demandé de factoriser plusieurs expressions mais je bloque sur l'une d'elles :
B(x) = x² - 2x + 1 + (3x+4)(x-1)
Je vous remercie d'avance !
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
gsantha
Verified answer
Bonjour
x² - 2x + 1 est une identité remarquable du type a²-2ab+b² = (a-b)² donc
x² - 2x + 1 = (x-1)²
B(x) = x² - 2x + 1 + (3x+4)(x-1)
= (x-1)² + (3x+4)(x-1)
= (x-1)[(x-1) + (3x+4)]
= (x-1)(x-1+3x+4)
= (x-1)(4x+3)
Voilà j'espère avoir pu t'aider ^^
3 votes
Thanks 1
oussama16
Verified answer
Bonjour ;
B (x)=x²-2x+1+(3x+4)(x-1)
Pour x²-2x+1 il prend la forme de (a-b)²=a²-2ab+b²
Alors B (x)=(x-1)²+(3x+4)(x-1)
B (x)=(x-1)[x-1+(3x+4)]
B (x)=(x-1)(x-1+3x+4)
B (x) =(x-1)(4x+3)
J'espère t'avoir t'aider, et j'espère que tu as compris, bonne journée ; )
1 votes
Thanks 0
More Questions From This User
See All
Liorasarah
February 2021 | 0 Respostas
Responda
Liorasarah
February 2021 | 0 Respostas
Responda
Liorasarah
January 2021 | 0 Respostas
Responda
Liorasarah
January 2021 | 0 Respostas
Responda
Liorasarah
January 2021 | 0 Respostas
Responda
Liorasarah
January 2021 | 0 Respostas
Bonjour, pouvez-vous m'aider pour la question 1 et 3 ? Je vous remercie !
Responda
Liorasarah
January 2021 | 0 Respostas
Responda
Liorasarah
January 2021 | 0 Respostas
Responda
Liorasarah
January 2021 | 0 Respostas
Responda
Liorasarah
January 2021 | 0 Respostas
Responda
×
Report "Bonjour, notre prof nous a demandé de factoriser plusieurs expressions mais je bloque sur l'une d'el.... Pergunta de ideia de Liorasarah"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjourx² - 2x + 1 est une identité remarquable du type a²-2ab+b² = (a-b)² donc
x² - 2x + 1 = (x-1)²
B(x) = x² - 2x + 1 + (3x+4)(x-1)
= (x-1)² + (3x+4)(x-1)
= (x-1)[(x-1) + (3x+4)]
= (x-1)(x-1+3x+4)
= (x-1)(4x+3)
Voilà j'espère avoir pu t'aider ^^
Verified answer
Bonjour ;B (x)=x²-2x+1+(3x+4)(x-1)
Pour x²-2x+1 il prend la forme de (a-b)²=a²-2ab+b²
Alors B (x)=(x-1)²+(3x+4)(x-1)
B (x)=(x-1)[x-1+(3x+4)]
B (x)=(x-1)(x-1+3x+4)
B (x) =(x-1)(4x+3)
J'espère t'avoir t'aider, et j'espère que tu as compris, bonne journée ; )