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Liorasarah
@Liorasarah
May 2019
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Bonjour, notre prof nous a demandé de factoriser plusieurs expressions mais je bloque sur l'une d'elles :
B(x) = x² - 2x + 1 + (3x+4)(x-1)
Je vous remercie d'avance !
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gsantha
Verified answer
Bonjour
x² - 2x + 1 est une identité remarquable du type a²-2ab+b² = (a-b)² donc
x² - 2x + 1 = (x-1)²
B(x) = x² - 2x + 1 + (3x+4)(x-1)
= (x-1)² + (3x+4)(x-1)
= (x-1)[(x-1) + (3x+4)]
= (x-1)(x-1+3x+4)
= (x-1)(4x+3)
Voilà j'espère avoir pu t'aider ^^
3 votes
Thanks 1
oussama16
Verified answer
Bonjour ;
B (x)=x²-2x+1+(3x+4)(x-1)
Pour x²-2x+1 il prend la forme de (a-b)²=a²-2ab+b²
Alors B (x)=(x-1)²+(3x+4)(x-1)
B (x)=(x-1)[x-1+(3x+4)]
B (x)=(x-1)(x-1+3x+4)
B (x) =(x-1)(4x+3)
J'espère t'avoir t'aider, et j'espère que tu as compris, bonne journée ; )
1 votes
Thanks 0
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Lista de comentários
Verified answer
Bonjourx² - 2x + 1 est une identité remarquable du type a²-2ab+b² = (a-b)² donc
x² - 2x + 1 = (x-1)²
B(x) = x² - 2x + 1 + (3x+4)(x-1)
= (x-1)² + (3x+4)(x-1)
= (x-1)[(x-1) + (3x+4)]
= (x-1)(x-1+3x+4)
= (x-1)(4x+3)
Voilà j'espère avoir pu t'aider ^^
Verified answer
Bonjour ;B (x)=x²-2x+1+(3x+4)(x-1)
Pour x²-2x+1 il prend la forme de (a-b)²=a²-2ab+b²
Alors B (x)=(x-1)²+(3x+4)(x-1)
B (x)=(x-1)[x-1+(3x+4)]
B (x)=(x-1)(x-1+3x+4)
B (x) =(x-1)(4x+3)
J'espère t'avoir t'aider, et j'espère que tu as compris, bonne journée ; )