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Ratpizer
@Ratpizer
June 2019
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Bonjour,
Parmi ces quatre formules, quelles sont celles qui sont toujours égales ?
•A=4*n-4
•B=4*(n-1)
•C=n+2*(n-1)+(n-2)
• D= 2*n+2*(n-2)
Merci d'avance.<3
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sarahmzn
Elle sont toutes égales car
A=4*n-4
=4*(n-1)
Donc A=B
C=n+2*(n-1)+(n-2)
=n+2*n-2+n-2
=4n-4
=4*(n-1)
Donc C=B
D=2*n+2*(n-2)
=2*n+2*n-4
=4*n-4
=4*(n-1)
Donc D=B
Conclusion:
A=B=C=D
0 votes
Thanks 1
ratpizer
Merciiiiiiiii
sarahmzn
De rien
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A=4*n-4
=4*(n-1)
Donc A=B
C=n+2*(n-1)+(n-2)
=n+2*n-2+n-2
=4n-4
=4*(n-1)
Donc C=B
D=2*n+2*(n-2)
=2*n+2*n-4
=4*n-4
=4*(n-1)
Donc D=B
Conclusion:
A=B=C=D