Bonjour,
(5x+2)(x-7) = 5x²-35x+2x-14 = 5x²-33x-14
2 couleurs noires (trèfle et pique) donc : 2/32 = 1/16 = 0,0625
f(x) = 3(x²-5)-(x-5)(3x+3)
= 3x²-15-(3x²+3x-15x-15)
= 3x²-15-3x²-3x+15x+15
= 12x
fonction linéaire de coefficient 12
l'antécédent de 2 est 3 et f(x) = (2/3)x
1 h 15 mn = 1 h (15/60) h = 1,25 h
vitesse = distance ÷ temps = 5 ÷ 1,25 = 4 km/h
5(-2)²+2(-2)-3 = 5(4)-4-3 = 20-4-3 = 13
prix - 15% = prix - prix × 15/100
= prix × 1 - prix × 15/100
= prix × (1 - 15/100)
= prix × 0,85
2⁻⁴ = 1/(2⁴) = 1/(2×2×2×2)
1 500 mL = 1,5 L = 1,5 dm³ (car 1 L = 1 dm³)
4 200 cm² = (4 200 ÷ 10²) dm² = 42 dm²
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,
(5x+2)(x-7) = 5x²-35x+2x-14 = 5x²-33x-14
2 couleurs noires (trèfle et pique) donc : 2/32 = 1/16 = 0,0625
f(x) = 3(x²-5)-(x-5)(3x+3)
= 3x²-15-(3x²+3x-15x-15)
= 3x²-15-3x²-3x+15x+15
= 12x
fonction linéaire de coefficient 12
l'antécédent de 2 est 3 et f(x) = (2/3)x
1 h 15 mn = 1 h (15/60) h = 1,25 h
vitesse = distance ÷ temps = 5 ÷ 1,25 = 4 km/h
5(-2)²+2(-2)-3 = 5(4)-4-3 = 20-4-3 = 13
prix - 15% = prix - prix × 15/100
= prix × 1 - prix × 15/100
= prix × (1 - 15/100)
= prix × 0,85
2⁻⁴ = 1/(2⁴) = 1/(2×2×2×2)
1 500 mL = 1,5 L = 1,5 dm³ (car 1 L = 1 dm³)
4 200 cm² = (4 200 ÷ 10²) dm² = 42 dm²