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Liiisaaa
@Liiisaaa
May 2019
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Bonjour
Pour cette équation " 1-1,1^n<-7 "
Est ce que on a le droit de faire 1,1^n<8
Sinon comment peut on faire ?
Merci d'avance
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greencalogero
Verified answer
Bonjour,
1-1.1^n<-7
1-1.1^n-1<-7-1
-1.1^n<-8
1.1^n>8
ln (1.1^n)>ln 8 car la fonction est croissante
n×ln(1.1)>ln 8 car ln(a^b)=b×ln(a)
n>ln(8)/ln(1.1)
n>21.82 au centième près.
1 votes
Thanks 1
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Bonjour, je comprends pas comment on trouve an+1= 0,6an+550 merci pour votre aide
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Lista de comentários
Verified answer
Bonjour,1-1.1^n<-7
1-1.1^n-1<-7-1
-1.1^n<-8
1.1^n>8
ln (1.1^n)>ln 8 car la fonction est croissante
n×ln(1.1)>ln 8 car ln(a^b)=b×ln(a)
n>ln(8)/ln(1.1)
n>21.82 au centième près.