Bonjour,
Réponse :
Rappels :
[tex]a^2+2ab+b^2=(a+b)^2\\a^2-2ab+b^2=(a-b)^2\\a^2-b^2=(a-b)(a+b)[/tex]
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a.
[tex]16x^{2} + 24x + 9=(4x)^{2} +2\times4x\times3+3^2=\boxed{(4x+3)^{2} }[/tex]
b.
[tex]49x^{2} - 70x + 25 = (7x)^{2} -2\times7x\times5+5^2=\boxed{(7x-5)^{2}}[/tex]
c.
[tex](5x-3)^2-81x^{2} \\=(5x-3)^2-(9x)^2\\=(5x-3-9x)(5x-3+9x)\\=\boxed{(-4x-3)(14x-3)}[/tex]
d.
[tex]25x^2 - (4x - 3)^2\\=(5x)^2 - (4x - 3)^2\\=[5x-(4x - 3)][5x+(4x - 3)]\\=(5x-4x + 3)(5x+4x - 3)\\=(x + 3)(9x - 3)\\=\boxed{3(x+3)(3x-1)}[/tex]
En espérant t'avoir aidé, bonne continuation ! :)
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Bonjour,
Réponse :
Rappels :
[tex]a^2+2ab+b^2=(a+b)^2\\a^2-2ab+b^2=(a-b)^2\\a^2-b^2=(a-b)(a+b)[/tex]
________________________________________________________
a.
[tex]16x^{2} + 24x + 9=(4x)^{2} +2\times4x\times3+3^2=\boxed{(4x+3)^{2} }[/tex]
b.
[tex]49x^{2} - 70x + 25 = (7x)^{2} -2\times7x\times5+5^2=\boxed{(7x-5)^{2}}[/tex]
c.
[tex](5x-3)^2-81x^{2} \\=(5x-3)^2-(9x)^2\\=(5x-3-9x)(5x-3+9x)\\=\boxed{(-4x-3)(14x-3)}[/tex]
d.
[tex]25x^2 - (4x - 3)^2\\=(5x)^2 - (4x - 3)^2\\=[5x-(4x - 3)][5x+(4x - 3)]\\=(5x-4x + 3)(5x+4x - 3)\\=(x + 3)(9x - 3)\\=\boxed{3(x+3)(3x-1)}[/tex]
En espérant t'avoir aidé, bonne continuation ! :)