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Haru27
@Haru27
April 2019
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Bonjour pourriez vous m'aider c'est urgent svp
g(x)=x cos (x) - sin (x)
Montrer que g'(x)= - x sin(x)
Dresser le tableau de signes de g'(x) sur [0;2pi]
Merci
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danielwenin
Verified answer
G'(x) = 1.cosx - x.sinx - cosx = -x.sinx
x 0 π 2π
-x 0 - -
sinx 0 + 0 - 0
g'(x) 0 - 0 + 0
0 votes
Thanks 1
danielwenin
c'est la dérivée d'un produit x.cosx => 1.cosx- x.sinx
danielwenin
on te sdemande juste le tableau de signe de g'(x)
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Verified answer
G'(x) = 1.cosx - x.sinx - cosx = -x.sinxx 0 π 2π
-x 0 - -
sinx 0 + 0 - 0
g'(x) 0 - 0 + 0