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Litapitou
@Litapitou
May 2019
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Bonjour, pourriez vous m'aider s'il vous plait ?
calculer en kilowattheure, puis en joule l'énergie consommée pendant 6 heures par un sèche-serviettes électrique de puissance 800 W
Merci d'avance ^-^
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scoladan
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Bonjour, E = Pxt = 800 x 6 = 4800 Wh = 4,8 kWh Pour obtenir E en Joules, il faut exprimer t en secondes. On sait que 1 h = 3600 s Donc E = 800 x 6 x 3600 = 17280000 J = 17,28 MJ (MegaJoules)
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Verified answer
Bonjour, E = Pxt = 800 x 6 = 4800 Wh = 4,8 kWh Pour obtenir E en Joules, il faut exprimer t en secondes. On sait que 1 h = 3600 s Donc E = 800 x 6 x 3600 = 17280000 J = 17,28 MJ (MegaJoules)