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Minouchou973
@Minouchou973
May 2019
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Bonjour pourriez vous m'aidez pour ce dm svp?
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nenette33
2)x varie sur EE' donc x varie de 0 à 10 cm
3) NH*NU=20 et
MN*EM=5 ⇒MN*x=5⇒MN=5/x
mais NH=MH-MN⇒NH=f(x)-MN et NU=EE'-EM⇒NU=10-x
donc NH*NU=20 devient [f(x)-MN](10-x)=20⇒f(x)-MN=20/(10-x)⇒
f(x)=MN-20/(10-x)⇒f(x)=5/x - 20/(10-x)
2 votes
Thanks 1
minouchou973
Merci beaucoup
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URGENT S'IL VOUS PLAIT AIDER MOI !!! merci
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3) NH*NU=20 et
MN*EM=5 ⇒MN*x=5⇒MN=5/x
mais NH=MH-MN⇒NH=f(x)-MN et NU=EE'-EM⇒NU=10-x
donc NH*NU=20 devient [f(x)-MN](10-x)=20⇒f(x)-MN=20/(10-x)⇒
f(x)=MN-20/(10-x)⇒f(x)=5/x - 20/(10-x)