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victoria05
@victoria05
January 2021
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Bonjour pouvais vous m'aider s'il vous plait j'ai besoin d'aide merci
1) sous forme a√6+b√3
2) sous forme a+b√2
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loulakar
Verified answer
1) perimetre :
Théorème de pythagore dans un triangle rectangle :
PE^2=(5V6)^2+(2V24)^2
PE^2=25x6+4x24
PE^2=150+96
PE^2=246
PE=V246
SE^2=(V2xV27)^2+(V246)^2
SE^2=2x27+246
SE^2 = 54+246
SE^2 = 300
SE = V300
SE = 10V3
Périmètre :
(V2xV27)+5V6+10V3+2V24
=V54+5V6+10V3+4V6
=3V6+5V6+10V3+4V6
=12V6 + 10V3
2) aire :
(2V24x5V6)/2 +
(10V3xV54)/2
(4V6x5V6)/2 + (10V3x3V6)/2
(10x6) + (15V18)
60 + 45V2
1 votes
Thanks 1
victoria05
mercii beaucoup ^^
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Verified answer
1) perimetre :Théorème de pythagore dans un triangle rectangle :
PE^2=(5V6)^2+(2V24)^2
PE^2=25x6+4x24
PE^2=150+96
PE^2=246
PE=V246
SE^2=(V2xV27)^2+(V246)^2
SE^2=2x27+246
SE^2 = 54+246
SE^2 = 300
SE = V300
SE = 10V3
Périmètre :
(V2xV27)+5V6+10V3+2V24
=V54+5V6+10V3+4V6
=3V6+5V6+10V3+4V6
=12V6 + 10V3
2) aire :
(2V24x5V6)/2 +
(10V3xV54)/2
(4V6x5V6)/2 + (10V3x3V6)/2
(10x6) + (15V18)
60 + 45V2