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SpyFox
@SpyFox
May 2019
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Bonjour pouvez-vous m’aider à FACTORISER cette expression s’il vous plaît !
5(3x - 5)(2x - 3)-(4x - 6)(4x + 1)
Merci d’avance !!
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MonsieurFirdown
Verified answer
Bonjour
♧ Factorisation :
5(3x-5)(2x-3)-(4x-6)(4x+1)
= 5(3x-5)(2x-3) - 2(2x-3)(4x+1)
= (2x-3)[5(3x-5)-2(4x+1)]
= (2x-3)(15x-25-8x-2)
= (2x-3)(7x-27)
Voilà ^^
0 votes
Thanks 2
SpyFox
Merci !!! ;-)
loulakar
Verified answer
Bonjour,
5(3x - 5)(2x - 3)-(4x - 6)(4x + 1) =
5(3x - 5)(2x - 3) - 2(2x - 3)(4x + 1) =
(2x - 3)[5(3x - 5) - 2(4x + 1)] =
(2x - 3)(15x - 25 - 8x - 2) =
(2x - 3)(7x - 27)
0 votes
Thanks 1
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Svp aidez-moi c'est pour demain !!!!!!
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Bonjour pouvez-vous m'aider svp c'est tout simple mais je n'y arrive pas !!
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Verified answer
Bonjour♧ Factorisation :
5(3x-5)(2x-3)-(4x-6)(4x+1)
= 5(3x-5)(2x-3) - 2(2x-3)(4x+1)
= (2x-3)[5(3x-5)-2(4x+1)]
= (2x-3)(15x-25-8x-2)
= (2x-3)(7x-27)
Voilà ^^
Verified answer
Bonjour,5(3x - 5)(2x - 3)-(4x - 6)(4x + 1) =
5(3x - 5)(2x - 3) - 2(2x - 3)(4x + 1) =
(2x - 3)[5(3x - 5) - 2(4x + 1)] =
(2x - 3)(15x - 25 - 8x - 2) =
(2x - 3)(7x - 27)