Bonjour,
(1/u)' = -(u'/u²)
On a donc f'(x) = 1/((x + 1)²)
Ainsi f'(-2) = 1/((-2 + 1)²) = 1/((-1)²) = 1/1 = 1
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Bonjour,
(1/u)' = -(u'/u²)
On a donc f'(x) = 1/((x + 1)²)
Ainsi f'(-2) = 1/((-2 + 1)²) = 1/((-1)²) = 1/1 = 1