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Poney38
@Poney38
May 2019
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Bonjour, pouvez vous m'aider à réaliser mon ex.
Soit k une fonction affine telle que
k(0) =4. Et k(5) =0
Déterminer une expression de k(x)
Merci
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no63
Verified answer
Salut
K(0)=4 et K(5)=0
K(x) est de la forme y=ax+b
calcul de a
a= (0-4)/(5-0)
a= -4/5
calcul de b
4= (-4/5)*0+b
b=4
K(x)= (-4/5)x+4
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Commentaires
Verified answer
Bonjour
forme ax + b
calcul de a
( 0 - 4) / ( 5 - 0) = - 4/5
a = - 4/5
k(5) = 0 ⇒ - 4/5 * 5 + b = 0 ⇒ - 20/5 + b = 0 ⇔ - 4 + b = 0 ⇔ b = 4
k(x) = - 4.5 x + 4
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Thanks 0
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Lista de comentários
Verified answer
SalutK(0)=4 et K(5)=0
K(x) est de la forme y=ax+b
calcul de a
a= (0-4)/(5-0)
a= -4/5
calcul de b
4= (-4/5)*0+b
b=4
K(x)= (-4/5)x+4
Verified answer
Bonjourforme ax + b
calcul de a
( 0 - 4) / ( 5 - 0) = - 4/5
a = - 4/5
k(5) = 0 ⇒ - 4/5 * 5 + b = 0 ⇒ - 20/5 + b = 0 ⇔ - 4 + b = 0 ⇔ b = 4
k(x) = - 4.5 x + 4