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84560
@84560
May 2019
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Bonjour, pouvez-vous m'aider à résoudre cette équation, je suis en seconde :
(7x+3)(9x-5)-(9x-5)=0
Merci pour votre aide !
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AbderraoufSlamani
Bonsoir
(7x + 3)(9x - 5) - (9x - 5) = 0
(9x - 5)(7x + 3 - 1) = 0
(9x - 5)(7x + 2) = 0
quand le produit égal à 0
donc si 9x - 5 = 0 --> 9x = 5 --> x = 5/9
ou 7x + 2 = 0 --> 7x = -2 --> x = -2/7
S = { 5/9 , -2/7}
1 votes
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84560
Merci beaucoup. :)
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(7x + 3)(9x - 5) - (9x - 5) = 0
(9x - 5)(7x + 3 - 1) = 0
(9x - 5)(7x + 2) = 0
quand le produit égal à 0
donc si 9x - 5 = 0 --> 9x = 5 --> x = 5/9
ou 7x + 2 = 0 --> 7x = -2 --> x = -2/7
S = { 5/9 , -2/7}