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Sreilerp
@Sreilerp
May 2019
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Bonjour pouvez-vous m'aider a résoudre cette équation sachant que je viens de rentrer en 1ere mais que c'est un révision de seconde:
Résoudre par le calcul l'équation 0,5 [ 5 - ( x-1 )² ] = 0
Merci d'avance :)
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Bonjour,
Résoudre 0,5 [ 5 - ( x-1 )² ] = 0 :
Identité remarquable : a² - b² = ( a+b )( a-b )
0,5 [ √5² - ( x-1 )² ] = 0
0,5( √5+x-1 )( √5-x+1 ) = 0
Produit nul :
x-1+√5 = 0
x = 1-√5
ou
-x+1+√5 = 0
-x = -1-√5
x = 1+√5
S = 1 ± √5
2 votes
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Verified answer
Bonjour,Résoudre 0,5 [ 5 - ( x-1 )² ] = 0 :
Identité remarquable : a² - b² = ( a+b )( a-b )
0,5 [ √5² - ( x-1 )² ] = 0
0,5( √5+x-1 )( √5-x+1 ) = 0
Produit nul :
x-1+√5 = 0
x = 1-√5
ou
-x+1+√5 = 0
-x = -1-√5
x = 1+√5
S = 1 ± √5