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Aylin005
@Aylin005
May 2019
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Bonjour
Pouvez vous m'aider pour ce dm j'arrive et c'est noté .
Merci beaucoup
Bônne journée
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croisierfamily
C' est rigolo, j' ai fait ça avec mes Elèves !
polygone triangle quadrilatère pentagone hexagone octogone
nb côtés 3 4 5 6 8
som(angles) 18o° 36o° 54o° 72o° 1o8o°
recherche de la Formule :
"n" côtés --> angle au centre = 36o/n
--> 2 angles de la part triangulaire = 18o - (36o/n) = 18o (1 -
2/n
)
-->
Somme TOTALE des angles
= n * 18o * (1 -
2/n
)
= 18o * (n-2)
3 votes
Thanks 1
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polygone triangle quadrilatère pentagone hexagone octogone
nb côtés 3 4 5 6 8
som(angles) 18o° 36o° 54o° 72o° 1o8o°
recherche de la Formule :
"n" côtés --> angle au centre = 36o/n
--> 2 angles de la part triangulaire = 18o - (36o/n) = 18o (1 - 2/n)
--> Somme TOTALE des angles = n * 18o * (1 - 2/n)
= 18o * (n-2)