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ebru7158
@ebru7158
January 2021
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Bonjour pouvez vous m'aider pour mon exercice de maths svpp qui est court mercii davance
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scoladan
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Bonjour,
a) Un = -5n + 7
⇒ Un+1 = -5(n + 1) + 7 = -5n + 2
⇒ Un+1 - Un = (-5n + 2) - (-5n + 7) = -5n + 2 + 5n - 7 = -5
Donc (Un) est arithmétique de raison r = -5 et de premier terme U₀ = 7
b) U₁ = 4 et ∀ n ≥ 2, Un = Un-1 + 4
⇒ Un - Un-1 = 4
⇒ (Un) arithmétique de raison r = 4 et de premier terme U₁ = 4
c) U₁ = 2 et ∀ n ≥ 1, Un+1 = Un + n - 1
⇔ Un+1 - Un = n - 1
⇒ non constant, donc (Un) n'est pas une suite arithmétique.
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Verified answer
Bonjour,a) Un = -5n + 7
⇒ Un+1 = -5(n + 1) + 7 = -5n + 2
⇒ Un+1 - Un = (-5n + 2) - (-5n + 7) = -5n + 2 + 5n - 7 = -5
Donc (Un) est arithmétique de raison r = -5 et de premier terme U₀ = 7
b) U₁ = 4 et ∀ n ≥ 2, Un = Un-1 + 4
⇒ Un - Un-1 = 4
⇒ (Un) arithmétique de raison r = 4 et de premier terme U₁ = 4
c) U₁ = 2 et ∀ n ≥ 1, Un+1 = Un + n - 1
⇔ Un+1 - Un = n - 1
⇒ non constant, donc (Un) n'est pas une suite arithmétique.