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MissRusse
@MissRusse
January 2021
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Bonjour,
Pouvez-vous m'aider pour mon exercice en maths ? Merci ! (je suis en troisième)
Factoriser les expressions suivantes en utilisant les identités remarquables :
a. 25 - x²
b. x² + 2x + 1
c. 49x² - 100
d. 4x² - 12x + 9
e. 16x² - 16
f. 64 - 48x + 9x²
Voilà, merci !
Cordialement
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maudmarine
Verified answer
Bonsoir,
a. 25 - x²
- (x + 5) (x + 5)
b. x² + 2x + 1
= (1 + x)²
c. 49x² - 100
= (7x - 10) (7x + 10)
d. 4x² - 12x + 9
= (2x - 3)²
e. 16x² - 16
= 16 (x² - 1)
f. 64 - 48x + 9x²
= (3x - 8)²
6 votes
Thanks 19
MissRusse
Bonsoir, merci ! :)
trudelmichel
Verified answer
Bonsoir,
il faut vraiment apprendre par coeur les identités
a:25-x²
25=5²
5²-x²
a²-b²=(a+b)(a-b)
5²-x²=(5+x)(5-x)
x²+2x+1
1=1² 2x=2(1*x) x²
(a+b)²=a²+2ab+b²
d'où
(x+1)²
49x²-100
49x²=(7x)²
100=10²
(7x)²-10²=(7x+10)(7x-10)
4x²-12x+9
4x²=(2x)²
9=3²
12x=2(2x*3)
d'où
a²-2ab+b²=(a-b)²
(2x-3)²
64-48x+9x²
9x²=(3x)²
64=8²
48x=2(3x*8)
d'où
a²-2ab+b²=(a-b)²
(3x-8)²
4 votes
Thanks 5
MissRusse
Bonsoir, merci beaucoup :)
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Lista de comentários
Verified answer
Bonsoir,a. 25 - x²
- (x + 5) (x + 5)
b. x² + 2x + 1
= (1 + x)²
c. 49x² - 100
= (7x - 10) (7x + 10)
d. 4x² - 12x + 9
= (2x - 3)²
e. 16x² - 16
= 16 (x² - 1)
f. 64 - 48x + 9x²
= (3x - 8)²
Verified answer
Bonsoir,il faut vraiment apprendre par coeur les identités
a:25-x²
25=5²
5²-x²
a²-b²=(a+b)(a-b)
5²-x²=(5+x)(5-x)
x²+2x+1
1=1² 2x=2(1*x) x²
(a+b)²=a²+2ab+b²
d'où
(x+1)²
49x²-100
49x²=(7x)²
100=10²
(7x)²-10²=(7x+10)(7x-10)
4x²-12x+9
4x²=(2x)²
9=3²
12x=2(2x*3)
d'où
a²-2ab+b²=(a-b)²
(2x-3)²
64-48x+9x²
9x²=(3x)²
64=8²
48x=2(3x*8)
d'où
a²-2ab+b²=(a-b)²
(3x-8)²