Bonjour pouvez vous m'aider svp pour ces 2 exercices.... Pergunta de ideia deTitouenseconde

Titouenseconde @Titouenseconde

January 2021 1 156 Report

Bonjour pouvez vous m'aider svp pour ces 2 exercices

Lista de comentários

noureddinealger

Réponse :

$b) \\Vn+1 = - ( n+1) / 2 = -n -1 / 2 \\ Vn+1 - Vn = -n-1 / 2 - (-n)/2 = -n-1+n / 2 = -1/2 ( raison) \\\\V0 = 0\\\\\\\\c) Wn+1 - Vn = 1 ( raison) \\W0 = 1/3$

Explications étape par étape

ex 60 : a) $a\\Un+1 = 2(n+1) -1 = 2n+2-1 = 2n +1Un+1 - Un = ( 2n+1) - (2n-1) = 2n + 1- 2n -1 = 2 ( la raison) \\\\U0 = 2 (0) -1 = - 1 ( terme initial )$

1 votes Thanks 1

More Questions From This User See All

Titouenseconde January 2021 | 0 Respostas

Bonjour pourriez vous m'aider pour mon exercice de math svp

Titouenseconde January 2021 | 0 Respostas

Titouenseconde January 2021 | 0 Respostas

Titouenseconde January 2021 | 0 Respostas

Titouenseconde January 2021 | 0 Respostas

Bonjour pouvez vous m'aider svp pour ces 2 exercices

Titouenseconde January 2021 | 0 Respostas

Titouenseconde January 2021 | 0 Respostas

Titouenseconde January 2021 | 0 Respostas

Titouenseconde January 2021 | 0 Respostas

Titouenseconde January 2021 | 0 Respostas

Helpful Links

Política de Privacidade

Termos e Condições

direito autoral

Helpful Social

Copyright © 2025 ELIBRARY.TIPS - All rights reserved.