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sbikania
@sbikania
January 2021
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Bonjour pouvez vous m'aidez s'il vous plaît merci
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chrystine
Bonsoir
1)le triangle ACO est rectangle en C
cos (COA)=CO/AO
cos(COA)=10/30=1/3
Arccos(1/3)=70.5°
2)le triangle OCB est rectangle en C,d'après le théorème de pythagore on a:
OB²=CO²+CB²
OB²=10²+1.6²
OB²=100+2.56
OB=√102.56
OB≈10.127m
b)tan (COB)=CB/CO
tan(COB)=1.6/10=0.16
Arctan(0.16)≈9.1°
3)70.5+9.1=79.6°≈80°
donc 80° trouvé par l'instrument de mesure est correcte
2 votes
Thanks 1
chrystine
de rien
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Lista de comentários
1)le triangle ACO est rectangle en C
cos (COA)=CO/AO
cos(COA)=10/30=1/3
Arccos(1/3)=70.5°
2)le triangle OCB est rectangle en C,d'après le théorème de pythagore on a:
OB²=CO²+CB²
OB²=10²+1.6²
OB²=100+2.56
OB=√102.56
OB≈10.127m
b)tan (COB)=CB/CO
tan(COB)=1.6/10=0.16
Arctan(0.16)≈9.1°
3)70.5+9.1=79.6°≈80°
donc 80° trouvé par l'instrument de mesure est correcte