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sbikania
@sbikania
January 2021
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Bonjour pouvez vous m'aidez s'il vous plaît merci
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croisierfamily
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1°) grâce à Pythagore, on trouve DF = 30 mètres .
DF² + DE² = EF² donne DF² + 16 ² = 34 ² donc DF² + 256 = 1156 donc
DF² = 1156 - 256 donc DF² = 900 d' où DF = racine carrée de 900 = 30 mètres
2°) cos DEF = adjacent / hypoténuse = 16 / 34 = 8 / 17
sin DEF = opposé / hypoténuse = 30 / 34 = 15 / 17
tan DEF = opposé / adjacent = 30 / 16 = 15 / 8
Remarque : on a bien cos² + sin² = 1
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Verified answer
1°) grâce à Pythagore, on trouve DF = 30 mètres .DF² + DE² = EF² donne DF² + 16 ² = 34 ² donc DF² + 256 = 1156 donc
DF² = 1156 - 256 donc DF² = 900 d' où DF = racine carrée de 900 = 30 mètres
2°) cos DEF = adjacent / hypoténuse = 16 / 34 = 8 / 17
sin DEF = opposé / hypoténuse = 30 / 34 = 15 / 17
tan DEF = opposé / adjacent = 30 / 16 = 15 / 8
Remarque : on a bien cos² + sin² = 1