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Kamaez
@Kamaez
April 2019
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Bonjour , pouvez vous m'aidez SVP
developper
1) 11 - (2x + 1) °
2) 5(t + 2)° - 10
3) 3 - 5(2y - 1)°
4) - ( x + 1) (3 - 2x)
factoriser
1) 64 - 4 ( 2t - 5)°
2) ( 2x + 1)° - ( 2x - 1 )°
° = carré
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telephone16
Développement
11 -(2x+1)²
11 - (4x² +4x +1) le deuxième terme est une identité remarquable
11 - 4x² -4x -1
-4x² +10 -4x
2) 5(t+2)² -10
5( t² +4 +4t) -10
5t² +20 +20t -10
5t² +20t +10
3) 3 - 5 ( 2y -1)²
3 -5 ( 4y² -4y +1)
3 -20y² +20y -5
-20y² +20y -2
4) - (x + 1 ) ( 3 - 2x)
- (3x -2x² +3 -2x)
-( -2x² +x +3)
+ 2x² -x -3
Factorisation
64 -4(2t-5)²
64 -4 (2t -5)(2t-5)
(2t-5) +60
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bonsoir , jai un devoir en francais que j'arrive pas a faire , aidez moi SVP Il faut ecrire un poeme sur l'amour , de 10 vers , avec des rimes et 3 figures de styles differents merci d'avance
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11 -(2x+1)²
11 - (4x² +4x +1) le deuxième terme est une identité remarquable
11 - 4x² -4x -1
-4x² +10 -4x
2) 5(t+2)² -10
5( t² +4 +4t) -10
5t² +20 +20t -10
5t² +20t +10
3) 3 - 5 ( 2y -1)²
3 -5 ( 4y² -4y +1)
3 -20y² +20y -5
-20y² +20y -2
4) - (x + 1 ) ( 3 - 2x)
- (3x -2x² +3 -2x)
-( -2x² +x +3)
+ 2x² -x -3
Factorisation
64 -4(2t-5)²
64 -4 (2t -5)(2t-5)
(2t-5) +60