Bonjour, pouvez-vous vérifiez mes résultats SVP ? Merci d'avance ! Factorisez les expressions suivantes :
A= (2t+1)²-(t+1)²
= [(2t+1)(t+1)] [(2t+1)(t-1)]
= (3t+2) 3t
B= (3t-7)²-25
= [(3t-7)+25] [(3t-7)-25]
= (3t-7+25) (3t-7-25)
= (3t+18) (3t-32)
C= (3t+4)²-(2t+3)²
=[(3t+4)(2t+3] [(3t+4)(2t-3)]
= (5t+7) (5t+1)
A= (2t+1)²-(t+1)²
= [(2t+1)(t+1)] [(2t+1)(t-1)]
= (3t+2) 3t
B= (3t-7)²-25
= [(3t-7)+25] [(3t-7)-25]
= (3t-7+25) (3t-7-25)
= (3t+18) (3t-32)
C= (3t+4)²-(2t+3)²
=[(3t+4)(2t+3] [(3t+4)(2t-3)]
= (5t+7) (5t+1)
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