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Biosignum
@Biosignum
January 2021
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bonjour qqlq peut m'aidez juste pour le premier exo svp
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scoladan
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Bonjour, 1) m=nxM = 40,00 x 0,0500 = 2,000 g.mol^-1 2) n=cxV = 0,15 x 250.10^-3 = 0,0375 mol 3) C=n/V et n=m/M donc C=m/(MxV) = 500.10^-3/(176,1 x 15.10^-2) = 19.10^-3 g.mol^-1
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Bonjour, 1) m=nxM = 40,00 x 0,0500 = 2,000 g.mol^-1 2) n=cxV = 0,15 x 250.10^-3 = 0,0375 mol 3) C=n/V et n=m/M donc C=m/(MxV) = 500.10^-3/(176,1 x 15.10^-2) = 19.10^-3 g.mol^-1