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Knssd
@Knssd
May 2019
1
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Bonjour qui pourrait m'aider pour cette operation svp merci bcp:
L=25x²-(3x²+1)²
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nadiab
Bonjour,
25x²-(3x²+1)²
Si c’est à factoriser
(5x)² -(3x²+1)²
(5x-3x²-1)(5x+3x²+1)
(-3x²+5x-1)(3x²+5x+1)
ou à développer
25x²-(3x²+1)²= 25x²-(9x
⁴
+3x²+3x²+1)
= 25x²- 9x⁴-6x²-1
= -9x⁴-19x²-1
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25x²-(3x²+1)²
Si c’est à factoriser
(5x)² -(3x²+1)²
(5x-3x²-1)(5x+3x²+1)
(-3x²+5x-1)(3x²+5x+1)
ou à développer
25x²-(3x²+1)²= 25x²-(9x⁴+3x²+3x²+1)
= 25x²- 9x⁴-6x²-1
= -9x⁴-19x²-1