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dyllan59
@dyllan59
January 2021
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Bonjour tout le monde pouvez vous m'aider à cette exercice merci.
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astroff
Verified answer
Salut !
Volume = aire de la base × hauteur
la base est un 1/4 de cercle de rayon 90 cm (donc : 9 dm)
aire de la base = (π × rayon²) ÷ 4 = 81π ÷ 4
hauteur de la douche = 190 cm (donc : 19 dm)
volume occupé = (81π ÷ 4) × 19 ≈ 1 209 dm³
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Verified answer
Salut !Volume = aire de la base × hauteur
la base est un 1/4 de cercle de rayon 90 cm (donc : 9 dm)
aire de la base = (π × rayon²) ÷ 4 = 81π ÷ 4
hauteur de la douche = 190 cm (donc : 19 dm)
volume occupé = (81π ÷ 4) × 19 ≈ 1 209 dm³