Explications étape par étape:
3) a)
x
x²
x² + 2x
x² + 2x - 15
b) (x - 3)(x + 5) = (x×x) + (x×5) - (3×x) - (3× 5) =
x² + 5x - 3x - 15 = x² + 2x - 15
c)(x - 3) (x + 5) = 0 donc:
x - 3 = 0 ou x + 5 = 0
_Si x -3 = 0 x = 3
_Si x + 5 = 0 x = -5
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Explications étape par étape:
3) a)
x
x²
x² + 2x
x² + 2x - 15
b) (x - 3)(x + 5) = (x×x) + (x×5) - (3×x) - (3× 5) =
x² + 5x - 3x - 15 = x² + 2x - 15
c)(x - 3) (x + 5) = 0 donc:
x - 3 = 0 ou x + 5 = 0
_Si x -3 = 0 x = 3
_Si x + 5 = 0 x = -5