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93harcorde
@93harcorde
May 2019
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Bonjour vous pouvez m'aidez MERCI
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croisierfamily
1°) angle BDC = 40° car (AB) // (DC) ( angles alternes internes ! )
2a) ADB = 180° - BAD - BDC = 180 - 100 - 40 = 180 - 140 = 40°
2b) demi-droite [ DB) = bissectrice angle ADC
3°) ADx = 180° - BDC - ADB = 180 - 40 - 40 = 180 - 80 = 100°
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2a) ADB = 180° - BAD - BDC = 180 - 100 - 40 = 180 - 140 = 40°
2b) demi-droite [ DB) = bissectrice angle ADC
3°) ADx = 180° - BDC - ADB = 180 - 40 - 40 = 180 - 80 = 100°