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AteZor
@AteZor
May 2019
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Bonjour vraiment très très urgent aidez moi svp
Exercice 3 et 4
Merci d'avance ^^^
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aur70
Verified answer
Bonjour
exo3
on utilise Pythagore
AB² + AC² = BC² ⇔ AC² = BC² - AB² ⇔ AC= √(BC² - AB²)
AC= √(7²-4²)=√(49-16)=√33=5.74 cm
cos ABC=AB/BC = 4/7 donc ABC=55°
sin ACB=AB/BC=4/7 donc ACB=35°
exo4
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Verified answer
Bonjourexo3
on utilise Pythagore
AB² + AC² = BC² ⇔ AC² = BC² - AB² ⇔ AC= √(BC² - AB²)
AC= √(7²-4²)=√(49-16)=√33=5.74 cm
cos ABC=AB/BC = 4/7 donc ABC=55°
sin ACB=AB/BC=4/7 donc ACB=35°
exo4
pas lisible sur ta photo