Articles
Register
Sign In
Search
Arch
@Arch
May 2019
1
98
Report
Bonjour,je suis au lycée en 2de et je dois faire le correction de mes exercices de physique mais je sèche sur le dernier, si vous pouviez m'expliquer comment faire :) ( Exercice sur la photo ci-jointe ).
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
scoladan
Verified answer
Bonjour,
Masse molaire moléculaire du dichlorométhane :
M = M(C) + 2xM(H) + 2xM(Cl) = 12 + 2x1 + 2x35,5 = 85 g.mol⁻¹
Pour prélever 0,25 mol, il faut donc prélever une masse de :
m = n x M = 0,25 x 85 = 21,25 g
Soit un volume de :
V = m/μ = 21,25/2,40 = 8,85 mL
0 votes
Thanks 0
More Questions From This User
See All
Arch
January 2021 | 0 Respostas
Responda
Arch
January 2021 | 0 Respostas
Responda
Arch
January 2021 | 0 Respostas
Responda
Arch
May 2019 | 0 Respostas
Responda
Arch
May 2019 | 0 Respostas
Responda
Recomendar perguntas
maceocoulon
November 2022 | 0 Respostas
lblbllbl
November 2022 | 0 Respostas
naelysvannier311
November 2022 | 0 Respostas
PikaS0ra
October 2022 | 0 Respostas
andronight67
October 2022 | 0 Respostas
kim036623
October 2022 | 0 Respostas
Tocam
October 2022 | 0 Respostas
leoniecch
October 2022 | 0 Respostas
Bobjour, pourriez vous m'aider pour le tableau
lillytrsn
October 2022 | 0 Respostas
charles5022
October 2022 | 0 Respostas
×
Report "Bonjour,je suis au lycée en 2de et je dois faire le correction de mes exercices de physique mais je .... Pergunta de ideia de Arch"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,Masse molaire moléculaire du dichlorométhane :
M = M(C) + 2xM(H) + 2xM(Cl) = 12 + 2x1 + 2x35,5 = 85 g.mol⁻¹
Pour prélever 0,25 mol, il faut donc prélever une masse de :
m = n x M = 0,25 x 85 = 21,25 g
Soit un volume de :
V = m/μ = 21,25/2,40 = 8,85 mL