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Asmaderbali11
@Asmaderbali11
May 2019
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Bonjours besoin d’aide merci
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NevaZyo
Distance de 10 mètres entre la chauve-souris et le moustique, et le signal doit effectuer un aller-retour.
Donc la distance parcourue par le signal en 0.058 secondes est de 20 mètres.
V= d/t = 20/0.058 = 344.83 m/s
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Lista de comentários
Donc la distance parcourue par le signal en 0.058 secondes est de 20 mètres.
V= d/t = 20/0.058 = 344.83 m/s