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Summersunshine
@Summersunshine
May 2019
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Bonjours ! Je suis en 3ème.
J'ai un devoir en maths sur les identités remarquables mais je n'ai pas compris comment faire vous pouvez m'expliquer ?
De plus j'ai des exercices à faire.
Voici les calculs :
A = (8x + 12) [Au Carré, le petit au dessus de la parenthèse]
B = (7 - 11x) [Au Carré, le petit au dessus de la parenthèse]
C = (50y - 5) (50y + 5)
D =(80y + 1) (80y - 1)
C'est pour Demain s'il vous plaît.
Merci.
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aur70
Verified answer
Bonjour
tu dois les savoir par coeur
(a+b)²=a²+2ab+b²
(a-b)²=a²-2ab+b²
a²-b²=(a+b)(a-b)
A=(8x+12)²=(8x)²+2*(8x)*12+12²=64x²+192x+144
B=(7-11x)²=7²-2*7*11x+(11x)²=49-154x+121x²
(50y-5)(50y+5)=(50y)²-5²=2500y²-25
(80y+1)(80y-1)=(80y)²-1²=6400y²-1
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Summersunshine
Je les sais par cœur mais je me trompe quand je calcule je ne sais pas si je dois garder le "au carré" après un calcule ou bien les enlever par exemple.
Summersunshine
Et merci beaucoup de ton aide
Commentaires (1)
Verified answer
Bonsoir,
A = (8x + 12)² = (a+b)² =a²+2ab+b²
= (8x)² + 2(8x*12) + 12²
= 64x²+192x+144
B = (7 - 11x)² = (a-b)² =a²-2ab+b²
= 7²-2(7*11x)+(11x)²
= 49-154x+121x²
= 121x²-154x+49
C = (50y - 5) (50y + 5) = (a-b)(a+b) = a²-b²
= (50y)² - 5²
= 2500y²-25
D =(80y + 1) (80y - 1) = (a+b)(a-b) =a²-b²
= (80y)²-1²
= 6400y²-1
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Summersunshine
Thanks
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Lista de comentários
Verified answer
Bonjourtu dois les savoir par coeur
(a+b)²=a²+2ab+b²
(a-b)²=a²-2ab+b²
a²-b²=(a+b)(a-b)
A=(8x+12)²=(8x)²+2*(8x)*12+12²=64x²+192x+144
B=(7-11x)²=7²-2*7*11x+(11x)²=49-154x+121x²
(50y-5)(50y+5)=(50y)²-5²=2500y²-25
(80y+1)(80y-1)=(80y)²-1²=6400y²-1
Verified answer
Bonsoir,A = (8x + 12)² = (a+b)² =a²+2ab+b²
= (8x)² + 2(8x*12) + 12²
= 64x²+192x+144
B = (7 - 11x)² = (a-b)² =a²-2ab+b²
= 7²-2(7*11x)+(11x)²
= 49-154x+121x²
= 121x²-154x+49
C = (50y - 5) (50y + 5) = (a-b)(a+b) = a²-b²
= (50y)² - 5²
= 2500y²-25
D =(80y + 1) (80y - 1) = (a+b)(a-b) =a²-b²
= (80y)²-1²
= 6400y²-1