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MrDro
@MrDro
May 2019
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Bonjours,
Mettre sous forme canonique le polynôme P(x)=x2−8x+7:
Merco de votre aide
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ProfdeMaths1
Verified answer
P(x)=x²−8x+7
=x²-8x+16-9
=
(x-4)²-9
2 votes
Thanks 0
MonsieurFirdown
Verified answer
Bonjour
♧ On a P(x) = x² - 8x + 7 d'où a = 1, b = - 8, et c = 7 ...
♧ On a donc :
● Alpha =
● Bêta = P(Alpha) d'où Bêta égale à :
P(x) = (4)² - 8×(4) + 7 = 16 - 32 + 7 = - 9
♧ Conclusion : la forme canonique est : (x-4)² - 9
Voilà ^^
0 votes
Thanks 1
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Verified answer
P(x)=x²−8x+7=x²-8x+16-9
=(x-4)²-9
Verified answer
Bonjour♧ On a P(x) = x² - 8x + 7 d'où a = 1, b = - 8, et c = 7 ...
♧ On a donc :
● Alpha =
● Bêta = P(Alpha) d'où Bêta égale à :
P(x) = (4)² - 8×(4) + 7 = 16 - 32 + 7 = - 9
♧ Conclusion : la forme canonique est : (x-4)² - 9
Voilà ^^