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Reep59
@Reep59
May 2019
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Bonjours pourriez vous m'aidez il faut factoriser l'expression (2a+1)(3a-5)-(3a-5)²
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Verified answer
Bonjour,
(3a-5)(2a+1-3a+5) =
(3a-5)(-a+6)
1 votes
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nadiab
Factoriser l'expression
(2a+1)(3a-5)-(3a-5)²
(3a-5)[(2a+1)-(3a-5)]
(3a-5)(2a+1-3a+5)
(3a-5)(-a+6)
2 votes
Thanks 0
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Verified answer
Bonjour,(3a-5)(2a+1-3a+5) =
(3a-5)(-a+6)
(2a+1)(3a-5)-(3a-5)²
(3a-5)[(2a+1)-(3a-5)]
(3a-5)(2a+1-3a+5)
(3a-5)(-a+6)