Δ =169
Δ > 0 ; 2 solutions x1 et x2
x1 = 6 et x2 = 5/3
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f(6)= -3(6)²+23(6)-30
f(6)=0
-3a²+23a-30 =0
Δ =169
Δ > 0 ; 2 solutions x1 et x2
x1 = 6 et x2 = 5/3