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Pink1515
@Pink1515
May 2019
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Bonsoir à tous! Quelqu'un peut m aider mon exercice s'il vous plait
Je bloque....
Merci!
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danielwenin
Verified answer
1) (x+7)(x-2)
2)-3(x² - x -12) = -3(x-4)(x+3)
3) 2(x² + 2x) + 7 => 2(x² + 2x + 1 -1) + 7 = 2((x² + 2x + 1) -1)+ 7 = 2(x+1)² - 2 + 7
=> 2(x+1)² + 5 pas factorisable
bonne soirée
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loulakar
delta = V(81) = 9
loulakar
delta > 0 donc deux solutions
loulakar
x1 = (-5 - delta)/(2*1) = (-5-9)/2 = -14/2 = -7
loulakar
x2 = (-5+delta)/(2*1) = (-5+9)/2 = 4/2 = 2
loulakar
donc l'équation peut s'écrire de la manière suivante : (x + 7)(x - 2)
loulakar
pour aller plus loin :
loulakar
l'équation de départ : ax^2 + bx + c avec : a = 1 b = 5 et c = -14. Delta^2 = (b)^2 - 4*a*c.
loulakar
Si delta > 0 deux solutions : x1 = (-b-delta)/(2*a) et x2 = (-b+delta)/(2*a)
loulakar
si delta = 0 une solution unique : x1=x2 = (-b)/(2*a)
loulakar
si delta < 0 pas de solution
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Verified answer
1) (x+7)(x-2)2)-3(x² - x -12) = -3(x-4)(x+3)
3) 2(x² + 2x) + 7 => 2(x² + 2x + 1 -1) + 7 = 2((x² + 2x + 1) -1)+ 7 = 2(x+1)² - 2 + 7
=> 2(x+1)² + 5 pas factorisable
bonne soirée