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Jelly19
@Jelly19
May 2019
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Bonsoir, c'est vrai que j'ai déjà poser ces qts ais je n'y arrive vmt pas
Merci d'avance. J'avais, grace a ceux qui m'ont répondu, réussit les autre question encore merci a eux.
Factoriser :
C = x² - 2x + 1 -(2x - 5)²
D = x(6x + 5) + 4(x-4)x
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Commentaires (2)
Bonsoir
c = ( x - 1)²- ( 2 x - 5)²
c = ( x - 1 + 2 x - 5) ( x - 1 - 2 x + 5)
c = (3 x - 6) ( - x + 4)
d ⇒ essaies de faire
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Jelly19
Ok merci vmt, mais tu peux m'expliquer en pv ou en commentaire prq tu as enlever le 2x et mit -1, j'ai pas tout compris ...
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c = ( x - 1)²- ( 2 x - 5)²
c = ( x - 1 + 2 x - 5) ( x - 1 - 2 x + 5)
c = (3 x - 6) ( - x + 4)
d ⇒ essaies de faire