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Sasala01
@Sasala01
May 2019
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Bonsoir j'ai besoin d'aide je n'ai pas compris merci beaucoup d'avance de votre aide
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ProfdeMaths1
Verified answer
On sait que cos(π/8)=√((2+√2)/4)
or cos²(π/8)+sin²(π/8)=1
donc sin²(π/8)=1-(2+√2)/4=(2-√2)/4
donc sin(π/8)=√((2-√2)/4)
1/3-1/8=(8-3)/24=5/24
donc cos(π/3-π/8)=cos(5π/24)
donc cos(5π/24)=1/2.√(2+√(2-√3))
et sin(5π/24)=1/2.√(2-√(2-√3))
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Liberté12
Bonjour tu peux m'aider pour mon devoir de maths s'il te plaît merci
ProfdeMaths1
bien sûr...
Liberté12
alors tu es où
sasala01
Merci beaucoupp
ProfdeMaths1
de rien
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Bonsoir je n'ai pas compris mon exercice merci beaucoup d'avance cordialement
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Verified answer
On sait que cos(π/8)=√((2+√2)/4)or cos²(π/8)+sin²(π/8)=1
donc sin²(π/8)=1-(2+√2)/4=(2-√2)/4
donc sin(π/8)=√((2-√2)/4)
1/3-1/8=(8-3)/24=5/24
donc cos(π/3-π/8)=cos(5π/24)
donc cos(5π/24)=1/2.√(2+√(2-√3))
et sin(5π/24)=1/2.√(2-√(2-√3))